Question

solve
(x^1/2y^2 ÷ x-3/2y4)​

Answer 1

Answer:

Step-by-step explanation:

Given that,

( x ^1 / 2y^2 ) ÷ ( x ^-3 / 2y^44 )

= ( x ^1 / 2y^2 ) × ( 2y^4 / x^-3 )

= ( x^1 × 2y^4 ) / ( 2y^2 × x^-3 )

= ( x^1 × y^2 ) / ( x^-3 )

= ( x^1 × y^2 × x^3 ) (∵x^- 3 = 1 / x^3 = 1/ ( 1/x^3) = x^3 )

= x ^4 y^2 is the answer. (∵Bases are equal, then powers should be add )

Answer 2

If the question is x^1/2y^2 then divided by x-3/2y^4