Math, asked by dhanushyaviiia, 6 months ago

solve. x-1/3 +( 5/3+x/2)=8​

Answers

Answered by aditya1154
0

Answer:

x -  \frac{1}{3}  + ( \frac{5}{3}  +  \frac{x}{2} ) = 8 \\  \frac{3x - 1}{3}  +  \frac{10 + 3x}{6}  = 8 \\  \frac{6x - 2 + 10 + 3x}{6}  = 8 \\  \frac{9x + 8}{6}  = 8 \\ 9x + 8 = 8 \times 6 \\ 9x = 48 - 8 \\ x =  \frac{40}{9}

Answered by srathnamala04
2

Answer:

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Step-by-step explanation:

−1⋅13+(53+2)=8

x-1 \cdot \frac{1}{3}+(\frac{5}{3}+\frac{x}{2})=8x−1⋅31+(35+2x)=8

Solve

1

Multiply the numbers

−1⋅13+(53+2)=8

x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{3}}}+(\frac{5}{3}+\frac{x}{2})=8x−1⋅31+(35+2x)=8

−13+(53+2)=8

x{\color{#c92786}{-\frac{1}{3}}}+(\frac{5}{3}+\frac{x}{2})=8x−31+(35+2x)=8

2

Eliminate redundant parentheses

−13+(53+2)=8

x-\frac{1}{3}+(\frac{5}{3}+\frac{x}{2})=8x−31+(35+2x)=8

−13+53+2=8

x-\frac{1}{3}+\frac{5}{3}+\frac{x}{2}=8x−31+35+2x=8

3

Add the numbers

−13+53+2=8

x{\color{#c92786}{-\frac{1}{3}}}+{\color{#c92786}{\frac{5}{3}}}+\frac{x}{2}=8x−31+35+2x=8

+43+2=8

x+{\color{#c92786}{\frac{4}{3}}}+\frac{x}{2}=8x+34+2x=8

4

Subtract 

43

\frac{4}{3}34

 from both sides of the equation

+43+2=8

x+\frac{4}{3}+\frac{x}{2}=8x+34+2x=8

+43+2−43=8−43

x+\frac{4}{3}+\frac{x}{2}{\color{#c92786}{-\frac{4}{3}}}=8{\color{#c92786}{-\frac{4}{3}}}x+34+2x−34=8−34

5

Simplify

Subtract the numbers

Subtract the numbers

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