Solve (x - 1)3x+2 +2(x - 1)242 - 4(x – 1 ) x + 4y = 4elog (log(x-1)). . - 2dy dx² dx
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Step-by-step explanation:
The given equation is
dx
dy
−
x+1
y
=e
3x
(x+1)
I.F. =e
∫−
x+1
1
dx
=e
−log(x+1)
=
x+1
1
The solution is
y(
x+1
1
)=∫e
3x
(x+1).
x+1
1
dx+a
⇒
x+1
y
=∫e
3x
dx+a=
3
e
3x
+a
⇒
x+1
3y
=e
3x
+c,c=3a
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