Solve (x + 1 < 5) ∩ (x - 4 > -3).
a. {all real numbers}
b. {x | 1 < x < 4}
c. {x | x < 4 or x > 1}
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x<4intersectionx>1=
and is option b
and is option b
TaniaParra11:
no, I have to say thank you for helping me in my question
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hope this help.........
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