solve (x - 1)(x + 1)(2x + 3)(2x - 1) = 3
solve step by step
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Answer:
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Step-by-step explanation:
(x - 1)(x + 1)(2x + 3)(2x - 1) = 3
or (x^2-1)(2x+3)(2x-1)=3
or 4X^4 +4x^3-7x^2-4x+3=3 (Expand my multiplying the terms with eachother)
or 4x^4+4x^3-7x^2-4x=0 As 3 goes to right side and they are cancelled
or x (4x^3+4x^2-7x-4)=0 x as common
or (2x+1)(2x^2+x-4)=0 using factoirzation method
now
(2x+1)=0 or (2x^2+x-4)=0
or x=-1/2 also x=(-1+root 33)/4 or (-1-root 33)/4 which is solved by the formula x = [−b ± √(b2 − 4ac)]/2a
Thats all
thank you
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