Question

Solve : (x + 1)(x + 2)(x + 3)(x + 4) + 1 = 0​

Answer 1

Step-by-step explanation:

-5root 5/2

hope it helps UHH

Answer 2

Answer:

It's Simple! here's the Answer.

(x+1)(x+2)(x+3)(x+4)=-1

((x+1)(x+4))((x+2)(x+3))=-1

(x^2+5x+4)(x^2+5x+6)=-1

Let's Y=x^2+5x

(Y+4)(Y+6)=-1

Y^2+10Y+24=-1

Y^2+10Y+25=0

(Y+5)^2=0

Y1=-5

Y2=-5

x^2+5x=Y1=-5

x^2+5x+5=0

x1=(-5+√(25–20))/2=(-5+√5)/2

x2=(-5-√(25–20))/2=(-5-√5)/2

x^2+5x=Y2=-5

x^2+5x+5=0

x3=(-5+√(25–20))/2=(-5+√5)/2

x4=(-5-√(25–20))/2=(-5-√5)/2

Done.

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