solve (x+1)(x+2)=(x-5)(x-6)
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Answered by
1
(x+1)(x+2)=(x-5)(x-6)
x^2 + 3x + 2 = x^2 - 11x + 30
14x = 28
Therefore,
x = 2
Hope this helps you!
x^2 + 3x + 2 = x^2 - 11x + 30
14x = 28
Therefore,
x = 2
Hope this helps you!
Answered by
1
(x +1)(x + 2) = (x-5)(x-6)
x²+x+2x+2 = x²-5x-6x-30
x²+3x+2 = x²-11x+30
3x + 2 = x² - 11x + 30 - x²
3x + 2 = -11x + 30
3x + 11x = 30 - 2
14 x = 28
x = 2
Hence,
LHS-
(2+1)(2+2)
= (3)(4)
= 12
RHS
(2-5)(2-6)
(-3)(-4)
= 12
Hence verified
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