solve (x+1) (x-3) +7=0
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1
hope it helps u!
→ (x+1)(x-3)+7=0
→ x^2-3x+x-3+7=0
→ x^2-2x-4=0
→ x^2-2x+2x-4=0
→ x(x-2)+2(x-2)=0
therefore,
either, x-2=0. or X+2=0
but x≠-2
hence, X= 2
→ (x+1)(x-3)+7=0
→ x^2-3x+x-3+7=0
→ x^2-2x-4=0
→ x^2-2x+2x-4=0
→ x(x-2)+2(x-2)=0
therefore,
either, x-2=0. or X+2=0
but x≠-2
hence, X= 2
Answered by
3
Answer:
2+i√12 & 2-i√12
Step-by-step explanation:
The pic on the above is correct...
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