Solve
|x+1| + |x| > 3
Answers
Answered by
1
Answer:
∣x−1∣≥∣x−3∣
⇒∣x−1∣−∣x−3∣≥0
∣x−1∣−∣x−3∣=
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−2
2x−4
2
if
if
if
x<1
1≤x≤3
x>3
if x<1
⇒−2≥0 not possible
if 1≤x≤3
⇒2x−4≤0⇒x≤2⇒x∈[2,∞)
∵1≤x≤3
⇒x∈[2,3]
if x>3
⇒2≤0 is true then
x∈(3,∞)
then x∈[2,3]∪(3,∞)
x∈[2,∞)
Answered by
1
6x^× +x—2 =0
a and b are zeroes of QUADRATIC EQUATION
6x^2 +4x--3x -2 =0 ( 6× -2 =--12 4×--3= --12 +4--3 =1)
2x(3x +2 ) -- 1(3x+2) =0
(2x-1 ) (3x+-2) =0
2x=1. x=1/2
3x=--2
x= --2/3
a = --2/3. b. . =1/2
Find the value of a/b +b/a
a/b = -- 4/3 b/ a = --3/4
a/b+b/a = -- 4/3 -- 3/4 = (—16 --9) /12 = --25 /12
The required value is --25/12
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