Math, asked by anmolsourav123, 12 days ago

Solve

|x+1| + |x| > 3​

Answers

Answered by krinapatel1604
1

Answer:

∣x−1∣≥∣x−3∣

⇒∣x−1∣−∣x−3∣≥0

∣x−1∣−∣x−3∣=

−2

2x−4

2

if

if

if

x<1

1≤x≤3

x>3

if x<1

⇒−2≥0 not possible

if 1≤x≤3

⇒2x−4≤0⇒x≤2⇒x∈[2,∞)

∵1≤x≤3

⇒x∈[2,3]

if x>3

⇒2≤0 is true then

x∈(3,∞)

then x∈[2,3]∪(3,∞)

x∈[2,∞)

Answered by xXItzSujithaXx34
1

6x^× +x—2 =0

a and b are zeroes of QUADRATIC EQUATION

6x^2 +4x--3x -2 =0 ( 6× -2 =--12 4×--3= --12 +4--3 =1)

2x(3x +2 ) -- 1(3x+2) =0

(2x-1 ) (3x+-2) =0

2x=1. x=1/2

3x=--2

x= --2/3

a = --2/3. b. . =1/2

Find the value of a/b +b/a

a/b = -- 4/3 b/ a = --3/4

a/b+b/a = -- 4/3 -- 3/4 = (—16 --9) /12 = --25 /12

The required value is --25/12

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