solve x^-16x-192 pls help me my maths exam
Answers
1.1 Factoring x2-16x-192
The first term is, x2 its coefficient is 1 .
The middle term is, -16x its coefficient is -16 .
The last term, "the constant", is -192
Step-1 : Multiply the coefficient of the first term by the constant 1 • -192 = -192
Step-2 : Find two factors of -192 whose sum equals the coefficient of the middle term, which is -16 .
-192 + 1 = -191 -96 + 2 = -94 -64 + 3 = -61 -48 + 4 = -44 -32 + 6 = -26 -24 + 8 = -16 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -24 and 8
x2 - 24x + 8x - 192
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-24)
Add up the last 2 terms, pulling out common factors :
8 • (x-24)
Step-5 : Add up the four terms of step 4 :
(x+8) • (x-24)
Which is the desired factorization
Equation at the end of step1:
(x + 8) • (x - 24) = 0
i hope this answer is helpful
Answer:
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