Question

solve :: x^2 + 1 = 0 for x​

Answer 1

Your answer...............

Answer 2

Answer:

$x = \iota \ or -\iota$

Step-by-step explanation:

We have been given the equation:-

$x^{2} + 1 = 0$

Transposing:-

$x^{2} = -1$

$x = \pm \sqrt{-1}$

It can be re-written as:-

$x = \pm \sqrt{1 \times -1}$

$x = \pm \sqrt{1} \times \sqrt{-1}$

$x = \pm 1 \times \sqrt{-1}$

We would be using the concept of Iota to simplify this further:-

Iota = $\sqrt{-1}$

$x = \pm 1 \times \iota$

$x = \pm \iota$

$x = \iota \ or -\iota$

So, the value of x is $\iota \ or -\iota$ !