Math, asked by amithrathi18497, 8 days ago

solve x/2-1/5=x/3+1/5​

Answers

Answered by etigupta30
0

answer

18

 \frac{5x - 2}{10}  =  \frac{5x - 3}{15}  \\ 15(5x - 2) = 10(5x + 30) \\ 65x - 30 = 50x + 300 \\ 65x - 50x = 300 - 30 \\ 15x = 270 \\ x =  \frac{270}{15}  \\ x = 18

Answered by MasterDhruva
7

Solution :-

We have two methods to solve this question, we'll solve both of them.

The first method is as follows.

\sf \leadsto \dfrac{x}{2} - \dfrac{1}{5} = \dfrac{x}{3} + \dfrac{1}{5}

\sf \leadsto \dfrac{5x - 2}{10} = \dfrac{5x + 3}{15}

\sf \leadsto 15(5x - 2) = 10(5x + 3)

\sf \leadsto 75x - 30 = 50x + 30

\sf \leadsto 75x - 50x = 30 + 30

\sf \leadsto 25x = 60

\sf \leadsto x = \dfrac{60}{25}

\sf \leadsto x = \dfrac{12}{5}

\:

Now, we'll find the value of x by an other method.

\sf \leadsto \dfrac{x}{2} - \dfrac{1}{5} = \dfrac{x}{3} + \dfrac{1}{5}

\sf \leadsto \dfrac{x}{2} - \dfrac{x}{3} = \dfrac{1}{5} + \dfrac{1}{5}

\sf \leadsto \dfrac{3x - 2x}{6} = \dfrac{1 + 1}{5}

\sf \leadsto \dfrac{1x}{6} = \dfrac{2}{5}

\sf \leadsto 5(1x) = 6(2)

\sf \leadsto 5x = 12

\sf \leadsto x = \dfrac{12}{5}

Therefore, the value of x is \sf \dfrac{12}{5}

Now, let's check that, our answer is right or wrong.

\sf \leadsto \dfrac{x}{2} - \dfrac{1}{5} = \dfrac{x}{3} + \dfrac{1}{5}

\sf \leadsto \dfrac{\dfrac{12}{5}}{2} - \dfrac{1}{5} = \dfrac{\dfrac{12}{5}}{3} + \dfrac{1}{5}

\sf \leadsto \bigg( \dfrac{12}{5} \times \dfrac{1}{2} \bigg) - \dfrac{1}{5} = \bigg( \dfrac{12}{5} \times \dfrac{1}{3} \bigg) + \dfrac{1}{5}

\sf \leadsto \dfrac{12}{10} - \dfrac{1}{5} = \dfrac{12}{15} + \dfrac{1}{5}

\sf \dashrightarrow \dfrac{12 - 2}{10} = \dfrac{12 + 3}{15}

\sf \dashrightarrow \dfrac{10}{10} = \dfrac{15}{15}

\sf \dashrightarrow 1 = 1

Thus, we can conclude that the answer obtained is correct.

Similar questions