Math, asked by ananduma246, 9 months ago

Solve x^2-10x-2=0 by completing the square

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Answered by konrad509
0

x^2-10x-2=0\\x^2-10x+25-27=0\\(x-5)^2=27\\x-5=\sqrt{27} \vee x-5=-\sqrt{27}\\x=5+3\sqrt3 \vee x=5-3\sqrt3

Answered by umiko28
0

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