Math, asked by ananduma246, 11 months ago

Solve x^2-10x-2=0 by completing the square

Answers

Answered by shaukatalijauhar
14

Answer:

5+3√3 , 5-3√3

Step-by-step explanation:

x^2-10x-2=0

=> (x^2-2*x*5+5^2)-5^2-2=0

by adding & subtracting 5^2

=> (x-5) ^2=27

as

( {a}^{2}   - 2ab +  {b}^{2} ) = ( {a - b)}^{2}

=> x-5 =+ /- √27

=>x= 5+3√3 , 5-3√3 Ans.

Answered by umiko28
15

Answer:

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Step-by-step explanation:

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