Question

Solve (x^2+12x)^2+35(x^2+12x)+150=0​

Answer 1

Answer:

(x^2+12x)^2+35(x^2+12x)+150=0

⇒(x^2+12x)^2+30(x^2+12x)+5(x^2+12x)+150=0

⇒(x^2+12x){(x^2+12x)+30}+5{(x^2+12x)30}=0

⇒{(x^2+12x)+5}{(x^2+12x)+30}=0

⇒(x^2+12x)+5=0 and (x^2+12x)+30=0

1. x^2+12x+5=0
2. x^2+12x+30=0

on solving equation 1  by quadratic formula

we get x = -6+√31 and -6-√31

similarly on solving equation 2 by quadratic formula(sridharacharya)

we get x = -6+√6 and -6-√6

therefore values of x are -6+√31,-6-√31,-6+√6 and -6-√6

Step-by-step explanation: