Question

solve (x-2)²+1=2x-3​

Answer 1

Answer:-

$\sf {(x - 2)}^{2} + 1 = 2x - 3$

$\sf \implies {x}^{2} - 4x + 4 + 1 = 2x - 3$

$\sf \implies {x}^{2} - 6x + 8 = 0$

$\sf \implies {x}^{2} - 2x - 4x + 8 = 0$

$\sf \implies x(x - 2) - 4(x - 2) = 0$

$\sf \implies (x - 4)(x - 2) = 0$

Therefore, either x-4=0 or x-2=0

So,

x=2,4

Hence, the roots of the given quadratic equation are 2 and 4.

Answer 2

Answer:

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