Question

solve x^2-(2+i)x=1-7i

Answer 1

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Answer 2

Answer:

The value of x are $x=\frac{(2+i)+\sqrt{7+32i}}{2},\frac{(2+i)-\sqrt{7+32i}}{2}$  

Step-by-step explanation:

Given : Expression $x^2-(2+i)x=1-7i$

To find : Solve the expression ?

Solution :

$x^2-(2+i)x-(1-7i)=0$

Solve by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=1 , b=-(2+i), c=-(1-7i)

Substitute the value in the formula,

$x=\frac{-(-(2+i))\pm\sqrt{(-(2+i))^2-4(-(1-7i))(1)}}{2(1)}$

$x=\frac{(2+i)\pm\sqrt{4-1+4i+4+28i}}{2}$

$x=\frac{(2+i)\pm\sqrt{7+32i}}{2}$

$x=\frac{(2+i)+\sqrt{7+32i}}{2},\frac{(2+i)-\sqrt{7+32i}}{2}$

Therefore, The value of x are $x=\frac{(2+i)+\sqrt{7+32i}}{2},\frac{(2+i)-\sqrt{7+32i}}{2}$