solve :x^2+2 root 3x +3=0
Answers
Answered by
0
Let's solve for o.
x2+2root(3)x+3=0
Step 1: Add -3 to both sides.
6o2rtx+x2+3+−3=0+−3
6o2rtx+x2=−3
Step 2: Add -x^2 to both sides.
6o2rtx+x2+−x2=−3+−x2
6o2rtx=−x2−3
Step 3: Divide both sides by 6rtx.
6o2rtx6rtx=−x2−36rtx
o2=−x2−36rtx
Step 4: Take square root.
o=√−x2−36rtx or o=−√−x2−36rtx
Answer:
o=√−x2−36rtx or o=−√−x2−36rtx
x2+2root(3)x+3=0
Step 1: Add -3 to both sides.
6o2rtx+x2+3+−3=0+−3
6o2rtx+x2=−3
Step 2: Add -x^2 to both sides.
6o2rtx+x2+−x2=−3+−x2
6o2rtx=−x2−3
Step 3: Divide both sides by 6rtx.
6o2rtx6rtx=−x2−36rtx
o2=−x2−36rtx
Step 4: Take square root.
o=√−x2−36rtx or o=−√−x2−36rtx
Answer:
o=√−x2−36rtx or o=−√−x2−36rtx
786786786786786:
what is that 6o
Similar questions