Question

solve (x^2 +2x)^2 = x^4+3+4x^2 by factorisation​

Answer 1

Answer:

(x^2+2x)^2=x^4+3+4x^2

x^4+4x^2+6x^2=x^4+3+16x^2

x^4+10x^2=x^4+3+16x^2

x^4-x^4=3+16x^2-10x^2

0=3+6x^2

-6x^2=3

-x^2=3/6

-x=root 3/6

x=-root 0.5