solve x^2-(3^-2+1)x+3^-2=0
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X^2 - 10x/9 + 1/9 =0
9X^2 - 10x + 1 = 0
9x^2 - 9x - x + 1 =0
9x(x - 1)-1(x - 1) =0
(9x-1)(x-1) = 0
x = 1/9, x = 1
9X^2 - 10x + 1 = 0
9x^2 - 9x - x + 1 =0
9x(x - 1)-1(x - 1) =0
(9x-1)(x-1) = 0
x = 1/9, x = 1
venkat35:
how is 3^-2=1/9
1/3^2 = 3^-2 so we can write it 1/9 = 9^-1
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