Question

solve : (x + 2)³ = 2x ( x²- 1 )​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Identity used here :-

$\bold{\boxed{{(x + y)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2} }}$

${(x + 2)}^{3} = 2x( {x}^{2} - 1)$

$= > {x}^{3} + {2}^{3} + 3 {x}^{2}(2) + 3x {(2)}^{2} = 2x( {x}^{2} - 1)$

$= > {x}^{3} + 8 + 6 {x}^{2} + 12x = 2 {x}^{3} - 2x$

$= > {x}^{3} - 2 {x}^{3} + 6 {x}^{2} + 12x + 2x + 8$

$= > - {x}^{3} + 6 {x}^{2} + 14x + 8$

$= > - {x}^{3} + 2(3 {x}^{2} + 7x + 4)$

$= > - {x}^{3} + 2(3 {x}^{2} + 4x + 3x + 4)$

$= > - {x}^{3} + 2[x(3 + 4) + 1(3x + 4)]$

$\bold{= > - {x}^{3} + 2[(3x + 4)(x + 1)]}$

$\bold\fcolorbox{aqua}{orange}{Answer}$$\bold{ - {x}^{3} + 2[(3x + 4)(x + 1)]}$