Question

solve:x^2-3√5x+10=0​

Answer 1

$2x^{2} - 3 \sqrt{5x} + 10$

$2x^{2} - 2 \sqrt{5}x - \sqrt{5}x + 10$

$x(2x - 2\sqrt{5}) - \sqrt{5}(x - 2 \sqrt{5})$

$(2x - 2 \sqrt{5})(x - \sqrt{5})$

$x = \frac{2 \sqrt{5} }{2} \: \: or \: \: x = \sqrt{5}$

$x = \sqrt{5} \: \: \: \: or \: \: x = \sqrt{5}$

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