Solve: x^2+3(x+3)=0. Find the answer correct to 2 decimal places.
Answers
Answered by
1
Answer:
x²+3(x+3)=0
x²+3x+9=0
but the discriminant is
b²-4ac
= 3²-4(1)(9)
=9-36
=-25 <0
hence no real roots exist
roots r imaginary
Answered by
1
- x² + 3(x+3) = 0
- x² + 3x+9=0
But the discriminant
- b² - 4ac
- 3²-4(1)(9)
- 9-36
- -25 < 0
Similar questions
Hindi,
5 months ago
Business Studies,
5 months ago
India Languages,
5 months ago
Math,
10 months ago