Solve x^2-3root5x+10 by factorisation
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Step-by-step explanation:
Given quadratic equation:
x²-3√5x+10=0
Splitting the middle term, we
get
=> x²-2√5x-√5x+10=0
=> x²-2√5x-√5x+2×5=0
=> x²-2√5x+√5x +2×√5×√5=0
=> x(x-2√5)-√5(x-2√5)=0
=> (x-2√5)(x-√5)=0
=> x-2√5 =0 Or x-√5 = 0
=> x = 2√5 Or x = √5
Therefore,
Roots of given Quadratic equation are:
2√5 Or √5
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