Question

solve x^2-3x+2<=0... please solve it using quadratic formula​

Answer 1

Answer:

Factoring x2-3x+2

The first term is, x2 its coefficient is 1 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is +2

Step-1 : Multiply the coefficient of the first term by the constant 1 • 2 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is -3 .

-2 + -1 = -3 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -1

x2 - 2x - 1x - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-2)

Add up the last 2 terms, pulling out common factors :

1 • (x-2)

Step-5 : Add up the four terms of step 4 :

(x-1) • (x-2)

Which is the desired factorization

Equation at the end of step

1

:

(x - 1) • (x - 2) = 0

STEP

2

:

Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Answer 2

Step-by-step explanation:

x²-3x+2=0

a=1 , b= -3 , c = 2

$x = \frac{ - b + - \sqrt{b {}^{2} - 4c } }{2a}$

$x = \frac{ - ( - 3)+ - \sqrt{( - 3) {}^{2} - 4(1)(2)} }{2(1)}$

$x = \frac{ 9+ - \sqrt{9 - 8} }{2}$

$x = \frac{ 9+ - \sqrt{1} }{2}$

$x = \frac{ 9+ - 1 }{2}$

$x = \frac{ 9+ 1 }{2} = \frac{10}{2} = 5 \\ or \\ x = \frac{ 9 - 1 }{2} = \frac{8}{2} = 4$