Question

Solve:
x^2+3x+5x-2/3x+5/9x-13=6/34

Answer 1

$x^2+3x+5x-\frac{2}{3}x+\frac{5}{9}x-13=\frac{3}{17}\\ \\x^2+x(9*3+9*5+\frac{-2*3+5}{9})-\frac{13*17-3}{17}=0\\ \\x^2+\frac{71}{9}x-\frac{218}{17}=0\\ \\2x = -\frac{71}{9}+-\sqrt{\frac{71^2}{9^2}-\frac{4*218}{17}}=$

x = - 3.944 +- 25.033 i 

The  solution is not a real number and it is an imaginary number.