Solve (x)^2 + 45x + 200 = 0
Find its Zero's or ROOTS
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here's ur answer
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Answer:
its zero's are minus 40 and minus 5
Step-by-step explanation:
x² +45x+200=0
x²+40x +5x+200=0
x(x+40) +5(x+40)=0
(x+40)(x+5)=0
x=-40 and x=-5
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