Question

Solve x^2-49=0 using quadratic formula

Answer 1

Answer:

$x = \pm 7$

Explanation:

Equation given => ${x}^{2} - 49 = 0$

We can write this equation in quadratic equation as follows:

$= > {x}^{2} + 0x - 49 = 0$

Quadratic Formula:

$= > x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

So, we can solve this equation with the help of quadratic formula as follows:

$= > b = 0 \\ \\ = > a = 1 \\ \\ = > c = - 49 \\ \\ \\ = > x = \frac{ - 0 \pm \sqrt{ {(0)}^{2} - 4(1)( - 49) } }{2(1)} \\ \\ = > x = \frac{ \pm \sqrt{0 - ( - 196)} }{2} \\ \\ = > x = \frac{ \pm \sqrt{196} }{2} \\ \\ = > x = \frac{ \pm \sqrt{ {(14)}^{2} } }{2} \\ \\ = > x = \frac{ \pm 14 }{2} \\ \\ = > x = \pm7$