Question

solve :
x^2-4root2x+6=0.

Answer 1

${x}^{2} - 4 \sqrt{2} x + 6 = 0 \\ {x}^{2} - 3 \sqrt{2} x - \sqrt{2} x + 6 = 0 \\ x(x - 3 \sqrt{2}) - \sqrt{2}(x - 3 \sqrt{2}) = 0 \\ (x - 3 \sqrt{2}) \: (x - \sqrt{2}) = 0 \\ x - 3 \sqrt{2} = 0 \: \: x - \sqrt{2} = 0 \\ x = 3 \sqrt{2} \: \: \: \: x = \sqrt{2}$