solve x^2+4x-5=0 by completing the square
friends help me fast
Answers
Answered by
1
Here is ur answer...hope it helps u!
Attachments:
Answered by
1
x^2+5x-x-5=0(splliting the middle term)
x(x+5)-(x+5)=0
(x+5)(x-1)=0
x=-5&x=1
x(x+5)-(x+5)=0
(x+5)(x-1)=0
x=-5&x=1
Similar questions