Question

Solve x^2+5x+4 by putting x =1
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Answer 1

Step-by-step explanation:

$x {}^{2} + 5x + 4 \\ (1) {}^{2} + 5(1) + 4 \\ 1 + 5 + 4 \\ 10$

I hope it helps you.........

Answer 2

$\huge\mathcal\colorbox{gold}{{\color{black}{ᴀɴSᴡᴇʀ~~~↓}}}$

$\sf \large Given: \\ \bf {x}^{2} + 5x + 4 \\ \sf \large when \: x = 1 \: we \: get : \\ \bf p(x) = {x}^{2} + 5x + 4 \\ \bf \therefore p(1) = ({1})^{2} + 5(1) + 4 \\ \bf = 1 + 5 + 4 = \underline{ \underline{10}}$

$\huge\sf{ʜᴏᴘᴇ~ɪᴛ~ʜᴇʟᴘs..!!}$