Question

Solve : x^2 -8x +16=0 by quadratic formula​

Answer 1

Step-by-step explanation:

x^2-8x+16=0

x^2-4x-4x+16=0

x (x-4)-4(x-4)=0

(x-4)(x-4)=0

hence, x=4

Answer 2

Answer:

(x-2)2-16=0

Two solutions were found :

x = 6

x = -2

Step by step solution :

Step 1 :

1.1 Evaluate : (x-2)2 = x2-4x+4

Trying to factor by splitting the middle term

1.2 Factoring x2-4x-12

The first term is, x2 its coefficient is 1 .

The middle term is, -4x its coefficient is -4 .

The last term, "the constant", is -12

Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .

-12 + 1 = -11

-6 + 2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2

x2 - 6x + 2x - 12

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-6)

Add up the last 2 terms, pulling out common factors :

2 • (x-6)

Step-5 : Add up the four terms of step 4 :

(x+2) • (x-6)

Which is the desired factorization

Equation at the end of step 1 :

(x + 2) • (x - 6) = 0

I HOPE IT WOULD HELP YOU AND MAKE ME BRAINIEST....