Question

solve(x^2-8x-3/8x-3)=(x^2+4x+4/4x+4)​

Answer 1

Answer:

please see the picture dear ....

Answer 2

The correct answer for this equation is 0, $\frac{7}{4}$.

Given,

$\frac{x^{2}-8x-3 }{8x-3} = \frac{x^{2}+4n+4 }{4n+4}$

To Find,

Simplify the above equation.

Solution,

We will solve the equation simultaneously,

$\frac{x^{2}-8x-3 }{8x-3} = \frac{x^{2}+4n+4 }{4n+4}$

cross multiply both the equations we get,

⇒(x² +8x³)(4x+4) = (8x³)(x²+4x+4)

⇒ 4x³+36x²+20x-12 = 8x³+29x²+20x-12

⇒ x²(4x+36) = x²(8x+29)

x = 0,

⇒ 4x+36 = 8x+29

⇒ 4x = 7

So, x = 0, $\frac{7}{4}$.

The correct answer for this equation is 0, $\frac{7}{4}$.

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