solve x^2-a^2+4xy+2ab-b^2+4y^2
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Answer:
x+2y-a+b
Step-by-step explanation:
x^2-a^2+4xy+2ab-b^2+4y^2
=x^2+4xy+4y^2=a^2-2ab+b^2 (bringing a^2-2ab+b^2 to the other side)
=(x+2y)^2=(a-b)^2 (the identities (a+b)^2 and (a-b)^2)
=
=x+2y=a-b
=x+2y-a+b
Hence the ans is x+2y-a+b.
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