Math, asked by saugatl606, 1 month ago

solve x^2-a^2+4xy+2ab-b^2+4y^2​

Answers

Answered by nibuprahladhan123
1

Answer:

x+2y-a+b

Step-by-step explanation:

x^2-a^2+4xy+2ab-b^2+4y^2​

=x^2+4xy+4y^2=a^2-2ab+b^2   (bringing a^2-2ab+b^2 to the other side)

=(x+2y)^2=(a-b)^2                      (the identities (a+b)^2 and (a-b)^2)

=\sqrt{(x+2y)^2=(a-b)^2}

=x+2y=a-b

=x+2y-a+b

Hence the ans is x+2y-a+b.

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