Question

solve (x^2-x)^2 + 5(x^2-x) +4=0​

Answer 1

Answer:

(x^2-x)^2+5(x^2-x)+4=0

let( x^2-x)=y

then ,

y^2+5y+4=0

=> y^2+4y+y+4=0

=> y(y+4)+1(y+4)=0

=> (y+4)(y+1)=0

putting the value of y

(x^2-x+4)(x^2-x+1)=0