Math, asked by nandanchowdary12, 1 month ago

solve
(x+2)(x+3)-(x+2)(x-3)=0
please solve this problem​

Answers

Answered by sahooabhinash59
2

Answer:

Step-by-step explanation:

(x+2)(x+3)-(x+2)(x-3)=0

(x^2 +3x+2x+6)-(x^2 -3x+2x-6)=0

x^2 +5x+6- x^2 +x +6=0

6x+12=0

6x= -12

x= -12/6

x= -2

OR

(x+2)(x+3)-(x+2)(x-3)=0

(x+2)[(x+3)-(x-3)]=0

(x+2)[x+3-x+3]=0

(x+2)(6)=0

(x+2)=0/6 = 0

x+2 =0

x=-2

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