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(x+2)(x+3)-(x+2)(x-3)=0
please solve this problem
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Answer:
Step-by-step explanation:
(x+2)(x+3)-(x+2)(x-3)=0
(x^2 +3x+2x+6)-(x^2 -3x+2x-6)=0
x^2 +5x+6- x^2 +x +6=0
6x+12=0
6x= -12
x= -12/6
x= -2
OR
(x+2)(x+3)-(x+2)(x-3)=0
(x+2)[(x+3)-(x-3)]=0
(x+2)[x+3-x+3]=0
(x+2)(6)=0
(x+2)=0/6 = 0
x+2 =0
x=-2
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