Question

solve (x+2/x-3)(x-2/x-3)​

Answer 1

AnswerGiven that,

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x

2

+2x+3x+6+x

2

−3x−2x+6−2x

2

−2x=0

⇒2x

2

−2x

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6

Answer 2

$\mathsf\red{Question : \:}\mathsf{\Bigg(\frac{x+2}{x-3}\Bigg) \times \Bigg(\frac{x - 2}{x + 3}\Bigg) }$

$\mathsf{}$

$\mathsf{ = \: \frac{(x + 2).(x - 2)}{(x - 3).(x + 3)} }$

$\boxed{\mathsf \blue{(a + b).(a - b) = {a}^{2} - {b}^{2} }}$

$\mathsf{ = \frac{ {x}^{2} - {2}^{2} }{ {x}^{2} - {3}^{2} } }$

$\mathsf{ = \: \frac{ {x}^{2} - 4 }{ {x}^{2} - 9 } }$