Question

Solve (x^2+x)(x^2+x-7)+10=0

Answer 1

Answer:

x=1 or

x=−2 or

x=1.79128784747792 or x=−2.79128784747792

Step-by-step explanation:

$= > \: (x^2+x)(x^2+x-7)+10=0 \\ \\ = > {x}^{4} + 2 {x}^{3} - 6 {x}^{2} - 7x + 10 = 0 \\ \\ = > Step 1: Factor \: \: left \: \: side \: \: of \: \: equation. \\ \\ = > \: (x - 1)(x + 2)(x ^{2} + x - 5) = 0 \\ \\ = >x - 1 = 0 \\ = > x + 2 = 0 \\ = > {x}^{2} + x - 5 = 0 \\ \\ now \\ = > x = 0 \\ = > x = - 2 \\ = > x = 1.79 \: \: or \: \: x = - 2.79</p><p></p><p></p><p>$

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