Question

solve (x^2+y^2+x)dx+xy dy =0​

Answer 1

$<marquee behaviour = "slide" direction="up" style="background : green">$

refer to the attachment

Answer 2

Given:

(x²+y²+x)dx + (xy)dy =0​

To Find:

solve the given expression.

Solution:

x²dx + y²dx + xdx + y(xdx) + x(ydx) = 0.

2x + 1 + y = 0.

2x + y +1 = 0.

Hence, the solution to the given expression is 2x + y + 1 = 0.