solve (x^2+y^2+x)dx+xy dy =0
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refer to the attachment
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Given:
(x²+y²+x)dx + (xy)dy =0
To Find:
solve the given expression.
Solution:
x²dx + y²dx + xdx + y(xdx) + x(ydx) = 0.
2x + 1 + y = 0.
2x + y +1 = 0.
Hence, the solution to the given expression is 2x + y + 1 = 0.
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