Solve (x/2+y/3)^3 + (x/2-y/3)^3 . It is of chapter polynomials
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Answer:
(x/2+y/2){(x^2/4)+(y^2/9)-xy/6}
Step-by-step explanation:
- x/2+y/3 ...................take this whole as "a"
- x/2-x/3.....,................take this whole as "b"
if u look at the given question
(x/2+y/3)^3.............is our a raised to power 3 or a^3
(x/2-y/3)^3..............is our b raised to power 3 or b^3
now we know the formula
a^3+b^3=(a+b)(a^2+b^2-ab)...
so u can see this in the form of above identity
so calculate:
(x/2+y/2)[X/2^2+y/3^2-x/2.y/2]
we wrote the above step in form of a^3+b^3 identity
if you do the process ..u will get
(x/2+y/2){(x^2/4)+(y^2/9)-xy/6}
hope this answer ....helps you
and mark me as brainliest ....
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