Solve x/2 -y/5=4, x/7 +y/15=3 by elimination method
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Solutions x = 14 and y = 15
Given:
x/2 -y/5=4 and x/7 +y/15=3 by
To find:
Solve the equations by elimination method
Solution:
Given x/2 -y/5=4
⇒ (5x - 2y)/10 = 4
⇒ 5x - 2y = 40 -----(1)
x/7 +y/15 = 3
⇒ (15x +7y)/105 = 3
⇒ 15x + 7y = 315 -----(2)
7×(1) = 35x - 14y = 280 ----(3)
2×(2) = 30x +14y = 630 ------(4)
Now add (3) and (4)
⇒ 35x - 14y +30x +14y = 280 + 630
⇒ 65x = 910
⇒ x = 14
Substitute x = 14 in (1)
⇒ 5(14) - 2y = 40
⇒ 70 - 2y = 40
⇒ 2y = 30
⇒ y = 15
Therefore, solutions x = 14 and y = 15
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