Question

solve x : √2x + √3y =0 , √3x - √8 = 0 by eliminating method​

Answer 1

Answer:

√3x=√8

x=√8/√3

√2×√8/√3+√3y=0

4√3=-√3y

y=-4

Answer 2

GIVEN :-

» √2x + √3y = 0 --------(i)

» √3x - √8y = 0 --------(ii)

multiplying equation (i) with √3 and equation (ii) with √2

» √6x + √9y = 0 ➡ √6x + 3y = 0 --------(iii)

» √6x - √16y = 0 ➡ √6x - 4y = 0 --------(iv)

subtracting (iv) from (iii) we get,

➡ (√6x + 3y) - (√6x - 4y) = 0

➡ √6x + 3y - √6x + 4y

➡ 3y + 4y = 0

➡ 7y = 0

➡ y = 0/7 = 0

putting value of y = 0 in equation (iii)

➡ √6x + 3(0) = 0

➡ √6x + 0 = 0

➡ x = 0/√6 = 0

hence the value of y = 0 and value of x = 0