Question

Solve x-2y=0; 3x+4y=20​

Answer 1

Given: x-2y=0

3x+4y=20

We need to find the values of x and y

x-2y=0 ————-(i)

3x+4y=20————-(ii)

Multiplying Equation (i) by 2 we get

2x-2y=0———–(iii)

Solving equations (ii) and (iii) we get,

3x+4y=20

2x-4y=0

_________

5x=20

x=5

Substituting the value of x in equation (i) we get,

5-2y=0

-2y=-5

2y=5

y=5/2

Hence x= 5 and y = 5/2

Answer 2

Answer:

The given equations are as follows: x – 2y = 0 ………….(i) 3x + 4y = 20 …………(ii) On multiplying (i) by 2, we get: 2x – 4y = 0 …………(iii) On adding (ii) and (iii), we get: 5x = 20 ⇒ x = 4 On substituting x = 4 in (i), we get: 4 – 2y = 0 ⇒ 4 = 2y ⇒ y = 2 Hence, the required solution is x = 4 and y = 2.