Question

Solve :
x+2y+2z = 2,
3x-2y-z = 5,
2x - 5y +3z =-4,
x+4y+6z= 0​

Answer 1

Step-by-step explanation:

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Answer 2

Linear Equations

The 4 linear equations in given in 3 variables,

$x+2y+2z = 2----------------(i)\\3x-2y-z = 5----------------(ii)\\2x - 5y +3z =(-4)--------------(iii)\\x+4y+6z= 0---------------(iv)$

On adding (i) and (ii), we get,

$4x+z=7---------------(v)$

Multiply equation (ii) with 2 and then add it with eq.(iv), we get,

$7x+4z=10----------------(vi)$

on solving equation is (v) and (vi), we get,

$x=2, \\z=-1$

hence, on putting value of x and z in any equation we get the value of y as 1.

So, the required value for x, y and z for these system of equation are 2, 1, -1 respectively.