Math, asked by romanakousar76, 6 days ago

solve : x^2y"-3xy'+3y=x+x^2

Answers

Answered by jyothiponnuri88

0

Answer:

give the question clearly

Answered by arvindkmr473

0

Answer:

x2y"−3xy′+3y=2x4ex

This is an Euler-Cauchy differential equation. Find the characteristic polynomial given y=xr to solve the homogenous equation.

Let y=xr,y′=rxr−1,y′=r(r−1)xr−2 .

x2y"−3xy′+3y=0

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