Question

solve x+2y-4=0, 3x+y-7=0 in elimination method​

Answer 1

Answer:

x+2y-4=0---------(1)×3

3x+y-7=0---------(2)×1

3x+6y-12=0

3x+ y -7. =0

(-) (-) (+)

__________

0. +5y-5 =0

5y=5

y=1

substitute y=1 by eq 1

x+2y-4=0

x+2(1)-4=0

x+2-4=0

x+(-2)=0

x=2