solve x+2y=7and x-3y= -8 by substitution method.
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Let,
x + 2y = 7 ———(1)
x - 3y = -8 ———(2)
Therefore, x = -8 +3y ———-(3)
Substituting the value of ‘x’ in equation (1) we get,
-8 + 3y + 2y = 7
5y = 15
y = 3
Now, putting value of ‘y’ in equation (3) we get,
x = -8 + 3y
x = -8 + 3*3
x = -8 + 9
x = 1
Therefore, the values of ’x’ an ‘y’ are 1 and 3 respectively.
I hope it helps you.
Plz mark it as brainliest.
Let,
x + 2y = 7 ———(1)
x - 3y = -8 ———(2)
Therefore, x = -8 +3y ———-(3)
Substituting the value of ‘x’ in equation (1) we get,
-8 + 3y + 2y = 7
5y = 15
y = 3
Now, putting value of ‘y’ in equation (3) we get,
x = -8 + 3y
x = -8 + 3*3
x = -8 + 9
x = 1
Therefore, the values of ’x’ an ‘y’ are 1 and 3 respectively.
I hope it helps you.
Plz mark it as brainliest.
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