Question

Solve x-3(2+x)>2(3x-1), x€{-3,-2,-1,0,1,2} also represent its solution on the number line.

Answer 1

solution on the number line.

We have 3x - 5 < 4

⇒ 3x - 5 + 5 < 4 + 5 (Add 5 to both sides)

⇒ 3x < 9

⇒ 3x/3 < 9/3 (Divide both sides by 3)

⇒ x < 3

So, the replacement set = {1, 2, 3, 4, 5, ...}

Therefore, the solution set = {1, 2} or S = {x : x ∈ N, x < 3}

Let us mark the solution set graphically.



Solution set is marked on the number line by dots. 

2. Solve 2x + 8 ≥ 18 

Here x ∈. W represent the inequation graphically

⇒ 2x + 8 - 8 ≥ 18 - 8 (Subtract 8 from both sides)

⇒ 2x ≥ 10

⇒ 2x/2 ≥ 10/2 (Divide both sides by 2)

⇒ x ≥ 5

Replacement set = {0, 1, 2, 3, 4, 5, 6, ...}

Therefore, solution set = {5, 6, 7, 8, 9, ...}

or, S = {x : x ∈ W, x ≥ 5}

Let us mark the solution set graphically.



Solution set is marked on the number line by dots. We put three more dots indicate infiniteness of the solution set.

3. Solve -3 ≤ x ≤ 4, x ∈ I

Solution:

This contains two inequations,

-3 ≤ x and x ≤ 4

Replacement set = {..., -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...}

Solution set for the inequation -3 ≤ x is -3, -2, -1, 0, 1, 2, ... i.e., S = {-3, -2, -1, 0, 1, 2, 3, ...} = P

And the solution set for the inequation x ≤ 4 is 4, 3, 2, 1, 0, -1, ... i.e., S = {..., -3, -2, -1, 0, 1, 2, 3, 4} = Q

Therefore, solution set of the given inequation = P ∩ Q

                          = {-3, -2, -1, 0, 1, 2, 3, 4}

or S = {x : x ∈ I, -3 ≤ x ≤ 4}

Let us represent the solution set graphically.