solve x-3(2+x)>2(3x-1),x€{-3,-2,-1,0,1,2} set builder form
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hey mate
here is the solution....
x-3(2+x)>2(3x-1) where x € {-3, ...2}
=>x-6-3x>6x-2
=>-2x-6>6x-2
=>-8x>4
=>x<4/-8
(reversing the sign of inequality as dividing both sides by -ve no)
=>x<-½
thus,
solution set :x={-3,-2,-1}
thus,
set builder form:{x:x€-z, -3<=X<=-1}
Anonymous:
welcome
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