Question

solve x+3/2x-7-2x-1/x-3=0​

Answer 1

Answer:

The Answer is (x= -3)..

Answer 2

$\frac{x+3}{2x-7} - \frac{2x-1}{x-3} = 0$

$\implies \frac{(x+3)(x-3) - (2x-7)(2x-1)}{((2x-7)(x-3)} = 0$

$\implies (x+3)(x-3) - (2x-7)(2x-1) = 0$

$\implies x^{2} - 9 - ( 4x^{2} - 2x - 14x + 7) = 0$

$\implies x^{2} - 9 - 4x^{2} + 2x + 14x - 7= 0$

$\implies - 3x^{2} + 16x - 16= 0$

$\implies 3x^{2} - 16x + 16= 0$

/* Splitting the middle term, we get */

$\implies 3x^{2} - 8x - 6x + 16= 0$

$\implies x(3x-8) - 2(3x-8) = 0$

$\implies (3x-8)(x-2) = 0$

$\implies 3x-8 = 0 \: Or \:x-2= 0$

$\implies 3x = 8 \: Or \:x= 2$

$\implies x = \frac{8}{3} \: Or \:x= 2$

Therefore.,

$\green { x = \frac{8}{3} \: Or \:x= 2}$

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